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(1/(3x+3))-(4/(x^2-1))=3/(x-1)
We move all terms to the left:
(1/(3x+3))-(4/(x^2-1))-(3/(x-1))=0
Domain of the equation: (3x+3))!=0
x∈R
Domain of the equation: (x^2-1))!=0
x∈R
Domain of the equation: (x-1))!=0We calculate fractions
x∈R
((1*(x^2-1))*x)/((3x+3))*(x^2-1))*(x-1)))+(-(4*(3x+3))*x)/((3x+3))*(x^2-1))*(x-1)))+(-(3*(3x+3))*x^2)/((3x+3))*(x^2-1))*(x-1)))=0
We can not solve this equation
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